Question
Evaluate:
$(0.2)^3-(0.3)^3+(0.1)^3$
$(0.2)^3-(0.3)^3+(0.1)^3$
✓
Answer
Let $\mathrm{a}=0.2, \mathrm{~b}=-0.3$ and $\mathrm{c}=0.1$
Then,
$a+b+c=0.2-0.3+0.1$
$=0.3-0.3$
$\Rightarrow a+b+c=0$
$\therefore a^3+b^3+c^3=3 a b c$
$\Rightarrow(0.2)^3+(-0.3)^3+(0.1)^3=3 \times(0.2) \times(-0.3) \times(0.1)$
$=-0.018$
Then,
$a+b+c=0.2-0.3+0.1$
$=0.3-0.3$
$\Rightarrow a+b+c=0$
$\therefore a^3+b^3+c^3=3 a b c$
$\Rightarrow(0.2)^3+(-0.3)^3+(0.1)^3=3 \times(0.2) \times(-0.3) \times(0.1)$
$=-0.018$
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