Question
Evaluate:
$(0.2)^3-(0.3)^3+(0.1)^3$
$(0.2)^3-(0.3)^3+(0.1)^3$
✓
Answer
Let $a=0.2, b=-0.3$ and $c=0.1$
Then, $a+b+c$
$=0.2-0.3+0.1$
$=0.3-0.3$
$\Rightarrow a+b+c=0$
$\therefore a^3+b^3+c^3=3 a b c$
$\Rightarrow(0.2)^3+(-0.3)^3+(0.1)^3$
$=3 \times(0.2) \times(-0.3) \times(0.1)$
$=-0.018$
Then, $a+b+c$
$=0.2-0.3+0.1$
$=0.3-0.3$
$\Rightarrow a+b+c=0$
$\therefore a^3+b^3+c^3=3 a b c$
$\Rightarrow(0.2)^3+(-0.3)^3+(0.1)^3$
$=3 \times(0.2) \times(-0.3) \times(0.1)$
$=-0.018$
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