Question
Evaluate$: 14 \sin 30^\circ + 6 \cos 60^\circ - 5 \tan 45^\circ .$
✓
Answer
$ 14 \sin 30^\circ + 6 \cos 60^\circ - 5 \tan 45^\circ$
$=14\left(\frac{1}{2}\right)+6\left(\frac{1}{2}\right)-5(1)$
$= 7 + 3 - 5$
$= 5.$
$=14\left(\frac{1}{2}\right)+6\left(\frac{1}{2}\right)-5(1)$
$= 7 + 3 - 5$
$= 5.$
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