Question
Evaluate:$ (3x - 1)(4x^3 - 2x^2 + 6x - 3)$
✓
Answer
$(3x - 1)(4x^3 - 2x^2 + 6x - 3)$
$= 3x (4x^3 - 2x^2 + 6x - 3) - 1 (4x^3 - 2x^2 + 6x - 3)$
$= 12x^4 - 6x^3 + 18x^2 - 9x - 4x^3 + 2x^2 - 6x + 3$
$= 12x^4 - 6x^3 - 4x^3 + 18x^2 + 2x^2 - 9x - 6x + 3$
$= 12x^4 - 10x^3 + 20x^2 - 15x + 3$
$= 3x (4x^3 - 2x^2 + 6x - 3) - 1 (4x^3 - 2x^2 + 6x - 3)$
$= 12x^4 - 6x^3 + 18x^2 - 9x - 4x^3 + 2x^2 - 6x + 3$
$= 12x^4 - 6x^3 - 4x^3 + 18x^2 + 2x^2 - 9x - 6x + 3$
$= 12x^4 - 10x^3 + 20x^2 - 15x + 3$
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