Question
Evaluate : $(3x−4y) (3x+4y) (9x^2+16y^2)$
✓
Answer
$(3x−4y) (3x+4y) (9x^2+16y^2)$
$= [(3x)^2−(4y)^2] (9x^2+16y^2)$
$= (9x^2−16y^2) (9x^2+16y^2)$
$= (9x^2)^2 − (16y^2)^2$
$= 81x^4 − 256y^4$
$= [(3x)^2−(4y)^2] (9x^2+16y^2)$
$= (9x^2−16y^2) (9x^2+16y^2)$
$= (9x^2)^2 − (16y^2)^2$
$= 81x^4 − 256y^4$
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