Maharashtra BoardEnglish MediumSTD 9MathsAlgebraic Identities2 Marks
Question
Evaluate:
$48^3-30^3-18^3$
✓
Answer
Let $a =48, b=-30$ and $c =-18$
Then, $a + b + c =48-30-18=0$
$\therefore a^3+b^3+c^3=3 a b c$
$\Rightarrow(48)^3+(-30)^3+(-18)^3$
$=3 \times(48) \times(-30) \times(-18)$
$=144 \times 540=77760$
$\therefore 48^3-30^3-18^3=77760$
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