Question
Evaluate: $\frac{-5}{-8}-\frac{-3}{4}$
✓
Answer
$\frac{-5}{-8}-\frac{-3}{4}$
$\frac{-5}{-8}=\frac{-5\times(-1)}{-8\times(-1)}=\frac{5}{8}$
$LCM$ of $8$ and $4 = 8$
$\therefore\frac{-3}{4}=\frac{-3\times2}{4\times2}=\frac{-6}{8}$
$\therefore\frac{-5}{-8}-\frac{-3}{4}$
$=\frac{5}{8}-\Big(\frac{-6}{8}\Big)$
$=\frac{5}{8}+\frac{6}{8}$
$=\frac{5+6}{8}$
$=\frac{11}{8}$
$\frac{-5}{-8}=\frac{-5\times(-1)}{-8\times(-1)}=\frac{5}{8}$
$LCM$ of $8$ and $4 = 8$
$\therefore\frac{-3}{4}=\frac{-3\times2}{4\times2}=\frac{-6}{8}$
$\therefore\frac{-5}{-8}-\frac{-3}{4}$
$=\frac{5}{8}-\Big(\frac{-6}{8}\Big)$
$=\frac{5}{8}+\frac{6}{8}$
$=\frac{5+6}{8}$
$=\frac{11}{8}$
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