Question
Evaluate $: (99)^2$
✓
Answer
$(99)^2 = (100 - 1)^2$
$= [(100) + (-1)]^2$
$= (100)^2 + 2 \times (100) \times (-1) + (-1)^2$
$= 10000 - 200 + 1$
$= 9801$
$= [(100) + (-1)]^2$
$= (100)^2 + 2 \times (100) \times (-1) + (-1)^2$
$= 10000 - 200 + 1$
$= 9801$
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