Question
Evaluate:
$(99)^2$
$(99)^2$
✓
Answer
$(99)^2=(100-1)^2$
$=[(100)+(-1)]^2$
$=(100)^2+2 \times(100) \times(-1)+(-1)^2$
$=10000-200+1$
$=9801$
$=[(100)+(-1)]^2$
$=(100)^2+2 \times(100) \times(-1)+(-1)^2$
$=10000-200+1$
$=9801$
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