Evaluate 3&2 -1&23 is: 1. 6-32 2. 6-2 3. 6+32 4. 6+2 - Vidyadip

Question

Evaluate $\begin{bmatrix}\sqrt{3}&\sqrt{2}\\-1&2\sqrt{3}\end{bmatrix}$ is:

$6-3\sqrt{2}$
$6-\sqrt{2}$
$6+3\sqrt{2}$
$6+\sqrt{2}$

✓

Answer

$6+\sqrt{2}$

Solution:

$\triangle=\begin{bmatrix}\sqrt{3}&\sqrt{2}\\-1&2\sqrt{3}\end{bmatrix}$

$\triangle=(\sqrt{3}\times2\sqrt{3})+\sqrt{2}$

$\triangle=6+\sqrt{2}$

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