MCQ
Evaluate $\begin{bmatrix}\sqrt{3}&\sqrt{2}\\-1&2\sqrt{3}\end{bmatrix}$ is:
- A$6-3\sqrt{2}$
- B$6-\sqrt{2}$
- C$6+3\sqrt{2}$
- ✓$6+\sqrt{2}$
✓
Answer
Correct option: D.
$6+\sqrt{2}$
$\triangle=\begin{bmatrix}\sqrt{3}&\sqrt{2}\\-1&2\sqrt{3}\end{bmatrix}$
$\triangle=(\sqrt{3}\times2\sqrt{3})+\sqrt{2}$
$\triangle=6+\sqrt{2}$
$\triangle=(\sqrt{3}\times2\sqrt{3})+\sqrt{2}$
$\triangle=6+\sqrt{2}$
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