Question
Evaluate:
$\Big(\frac{4}{3}\Big)^{-3}$
$\Big(\frac{4}{3}\Big)^{-3}$
$\Big(\frac{4}{3}\Big)^{-3}$
$=\Big(\frac{3}{4}\Big)^{3}$
$=\frac{3}{4}\times\frac{3}{4}\times\frac{3}{4}$
$=\frac{27}{64}$
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