Question
Evaluate:$\big(8\big)^{-\frac{1}{3}}$
✓
Answer
$\big(8\big)^{-\frac{1}{3}}=\frac{1}{\big(8\big)^{\frac{1}{3}}}=\frac{1}{\big(2^3\big)^{\frac{1}{3}}}=\frac{1}{2^{\big(3\times\frac{1}{3}\big)}}$$=\frac{1}{2^1}=\frac{1}{2}$
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