Question
Evaluate:
$\Big(\frac{-2}{3}\Big)^{-5}$

Answer

$\Big(\frac{-2}{3}\Big)^{-5}=\Big(\frac{-3}{2}\Big)^{5}$
$=\Big(\frac{-3}{2}\Big)\times\Big(\frac{-3}{2}\Big)\times\Big(\frac{-3}{2}\Big)\times\Big(\frac{-3}{2}\Big)\times\Big(\frac{-3}{2}\Big)$
$=\frac{-243}{32}$

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