Question
Evaluate:
$\Big(\frac{-2}{3}\Big)^{-5}$

Answer

$\Big(\frac{-2}{3}\Big)^{-5}$
$=\Big(\frac{3}{-2}\Big)^{5}$
$=\frac{3^{5}}{-2^{5}}$
$=\frac{243}{-32}$
$=\frac{243\times-1}{-32\times-1}$
$=\frac{-243}{32}$

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