Question
Evaluate:
$\Big(\frac{3}{4}\Big)^{-2}$
$\Big(\frac{3}{4}\Big)^{-2}$
✓
Answer
$\Big(\frac{3}{4}\Big)^{-2}$
$=\Big(\frac{4}{3}\Big)^{2}$
$=\Big(\frac{4^2}{3^2}\Big)$
$=\frac{16}{9}$
$=\Big(\frac{4}{3}\Big)^{2}$
$=\Big(\frac{4^2}{3^2}\Big)$
$=\frac{16}{9}$
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