Question
Evaluate:
$\Big(\frac{9}{8}\Big)^{-3}\times\Big(\frac{9}{8}\Big)^{2}$

Answer

$\Big(\frac{9}{8}\Big)^{-3}\times\Big(\frac{9}{8}\Big)^{2}$ $=\Big(\frac{9}{8}\Big)^{-3+2}$ $=\Big(\frac{9}{8}\Big)^{-1}$$=\frac{8}{9}$

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