Question
Evaluate: $\bigg\{\Big(\frac{-2}{3}\Big)^3\bigg\}^{-2}$
✓
Answer
$\bigg\{\Big(\frac{-2}{3}\Big)^3\bigg\}^{-2}$$=\Big(\frac{-2}{3}\Big)^{-6}$
$=\Big(\frac{3}{-2}\Big)^{6}$
$=\frac{3^6}{-2^6}$
$=\frac{729}{64}$
$=\Big(\frac{3}{-2}\Big)^{6}$
$=\frac{3^6}{-2^6}$
$=\frac{729}{64}$
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