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Exponents — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSExponents2 Marks
Question
Evaluate:
$\Bigg\{\Big(\frac{1}{3}\Big)^{-3}-\Big(\frac{1}{2}\Big)^{-3}\Bigg\}\div\Big(\frac{1}{4}\Big)^{-3}$
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Answer

$\Bigg\{\Big(\frac{1}{3}\Big)^{-3}-\Big(\frac{1}{2}\Big)^{-3}\Bigg\}\div\Big(\frac{1}{4}\Big)^{-3}$
$=\Big\{(3)^3-(2)^3\Big\}\div(4)^3$
$=(27-8)\div64$
$=\frac{19}{64}$

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