Question
Evaluate:
$\Bigg[\bigg\{\Big(\frac{-1}{3}\Big)^{2}\bigg\}^{-2}\Bigg]^{-1}$
$\Bigg[\bigg\{\Big(\frac{-1}{3}\Big)^{2}\bigg\}^{-2}\Bigg]^{-1}$
✓
Answer
$\Bigg[\bigg\{\Big(\frac{-1}{3}\Big)^{2}\bigg\}^{-2}\Bigg]^{-1}$$=\Big(\frac{-1}{3}\Big)^{2\times(-2)(-1)}$
$=\Big(\frac{-1}{3}\Big)^{4}$
$=\Big(\frac{-1}{3}\Big)\times\Big(\frac{-1}{3}\Big)\times\Big(\frac{-1}{3}\Big)\times\Big(\frac{-1}{3}\Big)$
$=\frac{1}{81}$
$=\Big(\frac{-1}{3}\Big)^{4}$
$=\Big(\frac{-1}{3}\Big)\times\Big(\frac{-1}{3}\Big)\times\Big(\frac{-1}{3}\Big)\times\Big(\frac{-1}{3}\Big)$
$=\frac{1}{81}$
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