Question
Evaluate:
$\cot\Big(\tan^{-1}\text{a}+\cot^{-1}\text{a}\Big)$

Answer

$\cot\Big(\tan^{-1}\text{a}+\cot^{-1}\text{a}\Big)$
$=\cot\Big(\frac{\pi}{2}\Big)$ $\Big[\because\ \tan^{-1}\text{x}+\cot^{-1}\text{x}=\frac{\pi}{2}\Big]$
$=0$

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