Question
Evaluate $\cot(\tan^{−1}(2x) + \cot^{−1}(2x))$

Answer

$\cot \left(\tan ^{-1}(2 x)+\cot ^{-1}(2 x)\right)=\cot \left(\frac{\pi}{2}\right)$
$=0 \quad \cdots \cdots \cdot\left[\because \tan ^{-1} x+\cot ^{-1} x=\frac{\pi}{2}\right]$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free