MCQ
Evaluate: $ \displaystyle \lim_{\text{x}\rightarrow 0}\frac{\sin \text{x}+\cos \text{x}}{\sin \text{x}-\cos\text{x}}$
  • A
    0
  • B
    1
  • C
    -1
  • D
    $∞$

Answer

  1. -1

Solution:

$ \displaystyle \lim_{\text{x}\rightarrow 0}\frac{\sin \text{x}+\cos \text{x}}{\sin \text{x}-\cos\text{x}}$

Substituting x = 0, we get

$= \displaystyle \lim_{\text{x}\rightarrow 0}\frac{\sin \text{x}+\cos \text{x}}{\sin \text{x}-\cos\text{x}}$

$= \displaystyle \lim_{\text{x}\rightarrow 0}\frac{\sin \text{0}+\cos \text{0}}{\sin \text{0}-\cos\text{0}}$

$ = \displaystyle \lim_{\text{x}\rightarrow 0}\frac{\ \text{0}+\text{1}}{0-1}$

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