Question
Evaluate $: \frac{\cos 22^{\circ}}{\sin 68^{\circ}}$
✓
Answer
$\frac{\cos 22^{\circ}}{\sin 68^{\circ}}$
$=\frac{\cos \left(90^{\circ}-68^{\circ}\right)}{\sin 68^{\circ}}$
$=\frac{\sin 68^{\circ}}{\sin 68^{\circ}}$
$=1$
$=\frac{\cos \left(90^{\circ}-68^{\circ}\right)}{\sin 68^{\circ}}$
$=\frac{\sin 68^{\circ}}{\sin 68^{\circ}}$
$=1$
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