Question
Evaluate:
$i^{131}+i^{49}$

Answer

$i^{131}+i^{49}$
$=\left(i^4\right)^{32} \cdot i^3+\left(i^4\right)^{12} \cdot i$
$=(1)^{32}(-i)+(1)^{12} \cdot i$
$=-i+i$
$=0$

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