Question
Evaluate $\int \frac{1}{x \log x} d x$

Answer

Let $I =\int \frac{1}{x \log x} d x$
Put $\log x=t$
$ \therefore \frac{1}{x} d x= dt$
$\therefore I =\int \frac{1}{ t } dt =\log | t |+ c$
$\therefore I =\log |\log x |+ c $

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