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MARCH 2024 — Maths STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceMathsMARCH 20241 Mark
Question
Evaluate: $\int \frac{1}{x^2+25} d x$
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Answer

$\int \frac{1}{x^2+25} d x$
$=\int \frac{1}{x^2+25} d x=\frac{1}{5} \tan ^{-1}\left(\frac{x}{5}\right)+C \quad \ldots .\left[\frac{1}{x^2+a^2} d x=\frac{1}{a} \tan ^{-1}\left(\frac{x}{a}\right)+c\right]$

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