MCQ
Evaluate: $\int \frac{d x}{5-8 x-x^2}$
  • A
    $\frac{1}{\sqrt{21}} \log \left|\frac{\sqrt{21}+x+4}{\sqrt{21}-x-4}\right|+C$
  • B
    $\frac{1}{2 \sqrt{21}} \log \left|\frac{\sqrt{21}+x+4}{\sqrt{21}-x-4}\right|+C$
  • C
    $\frac{1}{\sqrt{21}} \log \left|\frac{\sqrt{21}-x-4}{\sqrt{21}+x+4}\right|+C$
  • D
    $\frac{1}{2 \sqrt{21}} \log \left|\frac{\sqrt{21}-x-4}{\sqrt{21}+x+4}\right|+C$

Answer

$
\begin{array}{l}
\text { (b) : Let } I=\int \frac{d x}{5-8 x-x^2}=\int \frac{d x}{21-(x+4)^2} \\
=\int \frac{d x}{(\sqrt{21})^2-(x+4)^2}=\frac{1}{2 \sqrt{21}} \log \left|\frac{\sqrt{21}+x+4}{\sqrt{21}-x-4}\right|+C
\end{array}
$

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