Let $\text{I}=\int\frac{\sec^2\sqrt{\text{x}}}{\sqrt{\text{x}}}\text{ dx}$ Let $\sqrt{\text{x}}=\text{t}$ $\frac{\text{dx}}{2\sqrt{\text{x}}}=\text{dt}$ $\frac{\text{dx}}{\sqrt{\text{x}}}=2\text{dt}$ Putting $\sqrt{\text{x}}=\text{t}$ and $\frac{\text{dx}}{\sqrt{\text{x}}}=2\text{dt}$ $\therefore\ \text{I}=2\int\sec^2+\text{dt}$ $=2\tan\text{t}+\text{C}$ $=2\tan(\sqrt{\text{x}})+\text{C}$$(\because\text{t}=\sqrt{\text{x}})$
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