Question
Evaluate $\int e^{3 \log _e x} d x$ :

Answer

Let:
$
\begin{aligned}
I & =\int e^{3 \log _e x} d x \\
& =\int e^{\log _e x^3} d x=\int x^3 d x=\frac{1}{4} x^4+C
\end{aligned}
$

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