Question
Evaluate $\int \sqrt[3]{x^4} d x$.

Answer

Let
$
I=\int \sqrt(3){x^4} d x
$
$\Rightarrow \quad \int\left(x^4\right)^{\frac{1}{3}} d x=\int x^{\frac{4}{3}} d x$
$\Rightarrow \quad \frac{x^{\frac{4}{3}+1}}{\frac{4}{3}+1}=\frac{3}{7} x^{\frac{7}{3}}+ C$

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