Question
Evaluate : $\int \sqrt{\frac{x-5}{x-7}} \cdot d x$

Answer

$\mathrm{I}=\int \sqrt{\frac{(x-5) \cdot(x-5)}{(x-7) \cdot(x-5)}} \cdot d x=\int \sqrt{\frac{(x-5)^2}{x^2-12 x+35}} \cdot d x$
$
\because \quad \begin{aligned}
x-5 & =A \cdot \frac{d}{d x}\left(x^2-12 x+35\right)+B \\
x-5 & =A(2 x-12)+B \\
& =(2 A) x+(-12 A+B)
\end{aligned}
$
compairing, the co-efficients of like variables and constants
$
\begin{aligned}a
& 2 A=1 \text { and }-12 A+B=-5 \\
\Rightarrow & A=\frac{1}{2} \text { and } B=1
\end{aligned}
$
$\begin{aligned} & \mathrm{I}=\int \frac{\frac{1}{2} \cdot \frac{d}{d x}\left(x^2-12 x+35\right)+(1)}{\sqrt{x^2-12 x+35}} \cdot d x \\ & =\frac{1}{2} \cdot \int \frac{\frac{d}{d x}\left(x^2-12 x+35\right)}{\sqrt{x^2-12 x+35}} \cdot d x+\int \frac{1}{\sqrt{x^2-12 x+35}} \cdot d x \\ & =\mathrm{I}_1+\mathrm{I}_2 \\ & \therefore \quad I_1=\frac{1}{2} \cdot \int \frac{2 x-12}{\sqrt{x^2-12 x+35}} \cdot d x \\ & \text { put } x^2-12 x+35=t \\ & \therefore(2 x-12) \cdot d x=1 \cdot d t \\ & \mathrm{I}_1 \quad=\frac{1}{2} \cdot \int \frac{1}{\sqrt{t}} \cdot d t \\ & =\int \frac{1}{2 \sqrt{t}} \cdot d t \\ & =\sqrt{t}+c_1 \\ & =\sqrt{x^2-12 x+35}+c \\ & \end{aligned}$
$
\begin{aligned}
& \therefore \quad \mathrm{I}_2=\int \frac{1}{\sqrt{x^2-12 x+35}} \cdot d x \\
& =\int \frac{1}{\sqrt{x^2-12 x+36-1}} \cdot d x \\
& =\int \frac{1}{\sqrt{(x-6)^2-(1)^2}} \cdot d x \\
& \because \quad \int \frac{1}{\sqrt{X^2-A^2}} \cdot d x=\log \left(X+\sqrt{X^2-A^2}\right)+c \\
& \mathrm{I}_2 \quad=\log \left((x-6)+\sqrt{(x-6)^2-1}\right)+c_2 \\
& =\log \left((x-6)+\sqrt{x^2-12 x+35}\right)+c_2 \\
&
\end{aligned}
$
Thus, from (i), (ii) and (iii)
$
\begin{aligned}
& \int \sqrt{\frac{x-5}{x-7}} \cdot d x \\
= & \sqrt{x^2-12 x+35}+\log \left((x-6)+\sqrt{x^2-12 x+35}\right)+c \\
& \left(c_1+c_2=c\right)
\end{aligned}
$

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