Evaluate _0^1 d x 1+x^2 . - Vidyadip

Question

Evaluate $\int_0^1 \frac{d x}{1+x^2}$.

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Answer

$\int_0^1 \frac{d x}{1+x^2}=\left(\tan ^{-1} x\right)_0^1$
$=\tan ^{-1} 1-\tan ^{-1} 0=\frac{\pi}{4}-0=\frac{\pi}{4}$

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