Question
Evaluate: $\int_0^1|x| d x$
✓
Answer
$\int_0^1|x| d x-\int_0^1 x d x \quad \ldots . .[| x |= x , x \geq 0]$
$=\left[\frac{x^2}{2}\right]_0^{-1}$
$=\frac{1}{2}\left(1^2-0\right)$
$=\frac{1}{2}$
$=\left[\frac{x^2}{2}\right]_0^{-1}$
$=\frac{1}{2}\left(1^2-0\right)$
$=\frac{1}{2}$
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