Question
Evaluate : $\int_0^2 e^{3-4 x} d x$

Answer

$\text { (d) : We have, } \int_0^2 e^{3-4 x} d x=\left[\frac{e^{3-4 x}}{-4}\right]_0^2$
$=-\frac{1}{4}\left[e^{3-8}-e^{3-0}\right]=\frac{-1}{4}\left[e^{-5}-e^3\right]$

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