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Integrals — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsIntegrals1 Mark
MCQ
Evaluate : $\int_0^2 e^{3-4 x} d x$
  • A
    $\frac{-1}{4}\left(e^5-e^3\right)$
  • B
    $\frac{1}{4}\left(e^5-e^3\right)$
  • C
    $\frac{1}{4}\left(e^{-5}-e^3\right)$
  • D
    $\frac{-1}{4}\left(e^{-5}-e^3\right)$
✓

Answer

$
\begin{array}{l}
\text { (d) : We have, } \int_0^2 e^{3-4 x} d x=\left[\frac{e^{3-4 x}}{-4}\right]_0^2 \\
=-\frac{1}{4}\left[e^{3-8}-e^{3-0}\right]=\frac{-1}{4}\left[e^{-5}-e^3\right]
\end{array}
$

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