Maharashtra BoardEnglish MediumSTD 12 ScienceMathsDefinite Integration2 Marks
Question
Evaluate : $\int_0^3 x[x] \cdot d x$, where $[x]$ denote greatest integrate function not greater than $x$.
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Answer
$ \begin{aligned} \text { Let I } & =\int_0^3 x[x] \cdot d x \\ \qquad & =\int_0^1 x[x] \cdot d x+\int_1^2 x[x] \cdot d x+\int_2^3 x[x] \cdot d x \\ & =\int_0^1 x(0) \cdot d x+\int_1^2 x(1) \cdot d x+\int_2^3 x(2) \cdot d x \\ & =0+\left[\frac{x^2}{2}\right]_1^2+\left[x^2\right]_2^3 \\ & =0+\left(\frac{4}{2}-\frac{1}{2}\right)+(9-4) \\ & =\frac{3}{2}+5=\frac{13}{2} \\ \therefore \quad \int_0^3 x[x] \cdot d x & =\frac{13}{2} \end{aligned} $
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