Question
Evaluate $\int\frac{1-\sin\text{x}}{\cos^2\text{x}}\text{ dx}$

Answer

Let $\text{I}=\int\frac{1-\sin\text{x}}{\cos^2\text{x}}\text{ dx}$
$=\int\sec^2\text{x dx}-\int\sec\text{x}\tan\text{x dx}$
$\text{I}=\tan\text{x}-\sec\text{x}+\text{C}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free