Question
Evaluate $\int\left(1+x+\frac{x^2}{2 !}\right) d x$

Answer

$
\int\left(1+x+\frac{x^2}{2 !}\right) d x
$
$
\begin{aligned}
& =\int 1 d x+\int x d x+\frac{1}{2 !} \int x^2 d x \\
& =x+\frac{x^2}{2}+\frac{1}{2 !} \times \frac{x^3}{3}+c \\
& =x+\frac{x^2}{2}+\frac{x^3}{6}+c .
\end{aligned}
$

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