Question
$ \text{Evaluate} \int\limits_0^{1} \frac{dx}{1 + x^{2}}$

Answer

$\int\limits_0^{1} \frac{dx}{1 + x^{2}}=\big[\tan^{-1}\text{x}\big]^1_0$ 

$\tan^{-1}\perp-\tan^{-1}0$

$=\frac{\pi}{4}-0$

$=\frac{\pi}{4}$

 

 

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