Question
Evaluate:
$\int\sin\text{4x}\cos\text{3x dx}$.

Answer

Writing I = $\frac{1}{2}\int2\sin\text{ 4x }\cos\text{ 3x dx}=\frac{1}{2}\int(\sin\text{7x}+\sin\text{x) dx}$
$=\frac{1}{2}\Bigg[\frac{-\cos\text{ 7x}}{7}-\cos\text{x}\Bigg]+\text{c }\text{ OR }-\frac{1}{14}\cos\text{ 7x}-\frac{1}{2}\cos\text{ x + c}$.

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