Question
Evaluate: $\left(\frac{-8}{9}\right) \times\left(\frac{-3}{16}\right)$

Answer


$\begin{aligned} & \left(\frac{-8}{9}\right) \times\left(\frac{-3}{16}\right) \\ & =\frac{(-8) \times(-3)}{9 \times 16}=\frac{(-1) \times(-1)}{3 \times 2}=\frac{1}{6}\end{aligned}$

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