Question
Evaluate $: \sin (90^\circ - A) \sin A - \cos (90^\circ - A) \cos A$
✓
Answer
$ \sin (90^\circ - A) \sin A - \cos (90^\circ - A) \cos A$
$= \cos A \sin A - \sin A \cos A$
$= 0 $
$= \cos A \sin A - \sin A \cos A$
$= 0 $
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