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INVERSE TRIGNOMETRIC FUNCTIONS — MATHS STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 ScienceMATHSINVERSE TRIGNOMETRIC FUNCTIONS1 Mark
Question
$\text{Evaluate} : \sin \Bigg[\frac{\pi}{3} - \sin^{-1} \bigg( - \frac{1}{2}\bigg)\Bigg]$
✓

Answer

$\sin \Bigg[\frac{\pi}{3} - \sin^{-1} \bigg( - \frac{1}{2}\bigg)\Bigg] \sin \Bigg[\frac{\pi}{3} -\bigg( - \frac{\pi}{6}\bigg)\Bigg] = \sin\frac{\pi}{2} = 1$

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