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Inverse Trigonometric Functions — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsInverse Trigonometric Functions1 Mark
MCQ
Evaluate : $\sin \left[\frac{\pi}{3}+\sin ^{-1}\left(\frac{1}{2}\right)\right]$
  • A
    $\sqrt{3} / 2$
  • B
    $1 / 2$
  • C
    0
  • D
    1
✓

Answer

$
\begin{array}{l}
\text { (d) }: \sin \left(\frac{\pi}{3}+\sin ^{-1}\left(\frac{1}{2}\right)\right) \\
=\sin \left(\frac{\pi}{3}+\frac{\pi}{6}\right)=\sin \frac{\pi}{2}=1
\end{array}
$

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