Question
Evaluate $\sqrt{2.8}$ correct up to two places of decimal.

Answer

$\begin{array}{c|c} &1.673 \\ \hline 1 &2. \overline{80}\ \overline{00}\ \overline{00}\\& -1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ \hline26 &180\ \ \ \ \ \ \ \ \ \ \ \\ &-156\ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ \hline327 &\ 2400\ \ \ \ \ \ \\ &-2289\ \ \ \ \ \ \ \ \\ \hline \hline3343 &\ \ \ \ \ \ \ 11100\ \ \ \ \ \ \\ &\ \ \ \ -10029\ \ \ \ \ \ \ \ \\ \hline&\ \ \ \ \ \ \ \ \ \times\ \ \ \ \ \ \ \ \end{array}$
$\therefore\sqrt{2.8}=1.673=1.67$
(Correct up to two places of decimal)

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