Maharashtra BoardEnglish MediumSTD 8MathsCubes and Cube Roots2 Marks
Question
Evaluate:
$\sqrt[3]{-216}$
✓
Answer
We know that $\sqrt[3]{-216}=-\sqrt[3]{216}$
Resolving 216 into prime factors,
We get,
$216= \underline{2\times2\times 2}\times\underline{3\times3\times3}$
$= (2\times 3)^3$
$=(6)^3$
$\therefore\sqrt[3]{216}=6 $
$\therefore\sqrt[3]{-216}=-(\sqrt[3]{216})=-6 $
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.