Question
Evaluate:
$\sqrt[3]{\frac{-64}{343}}$

Answer

$\sqrt[3]{\frac{-64}{343}}$
$=\frac{\sqrt[3]{-64}}{\sqrt[3]{343}}$
$=\frac{\sqrt[3]{(-4)\times(-4)\times(-4)}}{\sqrt[3]{7\times7\times7}}$
$=\frac{-4}{7}$

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