Question
Evaluate: $\sqrt[3]{1728}$
✓
Answer
$\sqrt[3]{1728}$ By prime factorisation, we have$1728=\underline{2\times2\times2}\times\underline{2\times2\times2}\times\underline{3\times3\times3}$
$= (2\times2\times3)^3$ $= (12)^3$ $\therefore\sqrt[3]{1728}=12$
$= (2\times2\times3)^3$ $= (12)^3$ $\therefore\sqrt[3]{1728}=12$
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