Evaluate: [3] 27 + [3] 0.008 + [3] 0.064 - Vidyadip

Question

Evaluate: $\sqrt[3]{27}+\sqrt[3]{0.008}+\sqrt[3]{0.064}$

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Answer

We have, $\sqrt[3]{27}+\sqrt[3]{0.008}+\sqrt[3]{0.064}$
$=(27)^\frac{1}{3}+(0.008)^\frac{1}{3}+(0.064)^\frac{1}{3}$
$=(3\times3\times3)^\frac{1}{3}+(0.2\times0.2\times0.2)^\frac{1}{3}$
$+(0.4\times0.4\times0.4)^\frac{1}{3}$
$=(3)^{3\times\frac{1}{3}}+(0.2)^{3\times\frac{1}{3}}+(0.4)^{3\times\frac{1}{3}}$
$=3+0.2+0.4=3.6$

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